Corner Helmholtz - Triangle shape?

stonerbox 🎙️ · 15th April 2020

Forgive me if this have been covered before.

Is it possible to calculate or build a successful Helmholtz outside of the traditional square and cylinder shapes? I'm planing to dampen 45 Hz with about 6-8 dB. Yes, it is because I would like to conserve space if possible.

Sorry about the ugly illustration.

avare · 15th April 2020

Quote:

Originally Posted by stonerbox ➡️

Forgive me if this have been covered before.

Is it possible to calculate or build a successful Helmholtz outside of the traditional square and cylinder shapes? I'm planing to dampen 45 Hz with about 6-8 dB. Yes, it is because I would like to conserve space if possible.

Sorry about the ugly illustration.

Yes. The area of a triagle equals one half the height. Use one half the height as the depth.

stonerbox 🎙️ · 16th April 2020

Quote:

Originally Posted by avare ➡️

Yes. The area of a triagle equals one half the height. Use one half the height as the depth.

I'm having issues decrypting your post. If you could please expand on you idea for me.
Could I calculate a regular rectangular box for the double frequency ( 90 Hz ) then split or double it to get right frequency ( 45 Hz ) for my build? I'm however not sure how to accurately calculate the size of the holes that way.

Jason Foi · 16th April 2020

Calculate the volume of the cavity and use that number. Volume/hole size/hole spacing = tuning

Its a right angle, so (length x width x height) ÷ 2 = volume

Storm Mastering · 16th April 2020

The missing words for understanding Andre's answer

Quote:

Yes. The area of a triangle equals one half the height times its width / base. Use one half the height as the depth.

In others words, as it is a isosceles, right-angled triangle, calculate your Helmholtz as if it were a rectangle of the same visible width, with the depth taken as the distance from the middle of the base to the corner divided by 2.

edit : Jason was faster

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